ST.PETER'S B.ED COLLEGE KOLENCHERY DOC BLOG

Here are clear, exam-ready answers for Basic Concepts of Chemistry – Frequently Asked Previous Questions ✅ 1. NO and NO₂ are two oxides of nitrogen. Which law is illustrated? Law: Law of Multiple Proportions Statement: When two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in the ratio of small whole numbers. Proposed by: John Dalton 2. State Law of Definite (Constant) Proportions. Statement: A given compound always contains the same elements combined in the same fixed proportion by mass, irrespective of the source. Proposed by: Joseph Proust 3. State Law of Conservation of Mass. Statement: Mass is neither created nor destroyed in a chemical reaction; total mass of reactants equals total mass of products. Proposed by: Antoine Lavoisier 4. Define atomic mass unit (amu). Answer: One atomic mass unit is defined as 1/12th of the mass of a carbon-12 atom . 5. Define 1 mole. ...

ഇവ Plus One THERMODYNAMICS – VERY SIMPLE PROBLEMS ആണ് 👉 Chemistry + Physics , step-by-step solutions സഹിതം 😊 🔵 CHEMISTRY – Simple Thermodynamics Problems Q1. A system absorbs 100 J of heat and does 20 J of work. Find ΔU . Formula (Chemistry): \Delta U = q + w Given: q = +100 J w = –20 J (work done by system) Solution: \Delta U = 100 + (-20) = \boxed{80\ \text{J}} Q2. A system releases 50 J of heat and 30 J of work is done on it. Find ΔU . q = –50 J w = +30 J \Delta U = -50 + 30 = \boxed{-20\ \text{J}} Q3. At constant pressure, heat absorbed is 200 J . Find ΔH . Formula: \Delta H = q_p \Delta H = \boxed{200\ \text{J}} Q4. Is the reaction exothermic or endothermic if ΔH = –75 kJ ? 👉 Exothermic reaction (heat released) 🟢 PHYSICS – Simple Thermodynamics Problems Q5. A gas absorbs 500 J of heat and does 200 J of work. Find ΔU . Formula (Physics): \Delta U = Q - W Q = +500 J W = +200 J \Delta U = 500 - 200 = \boxed{300\ \text{J}}...

We have to find: 🔹 Step 1: Use the basic formula P(A \cup B) = P(A) + P(B) - P(A \cap B) 🔹 Step 2: Substitute the given values 0.6 = 0.35 + P(B) - 0.25 🔹 Step 3: Simplify 0.6 = 0.10 + P(B) P(B) = 0.6 - 0.10 = 0.5 ✅ Answer 1: \boxed{P(B) = 0.5} 🔹 Step 4: Find P(not B) P(\text{not }B) = 1 - P(B) P(B') = 1 - 0.5 = 0.5 ✅ Answer 2: \boxed{P(\text{not }B) = 0.5} 🌟 Final Answers P(B) = 0.5 P(not B) = 0.5 🧠 Easy Memory Tip Union formula → add – subtract Not B → 1 − B Below are the answers with very simple explanations , written in Plus One exam style 👍 (1 mark each – easy to remember) (i) If A ⊂ B, then A ∪ B = ? ✅ Answer: A \cup B = B Explanation (Simple): A is a subset of B All elements of A are already in B Union means all elements 👉 So, union gives the bigger set B (ii) Write the set { x : x is a positive integer and x² < 40 } in roster form Step 1: Check values ✔ ✔ ✔ ✔ ✔ ✔ ...

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*Big change coming!!!*  The Union Cabinet has approved the Higher Education Commission of India (HECI) Bill, now renamed as the *Viksit Bharat Shiksha Adhikshan Bill (VBSAB).* This is a structural reset. What it means in plain language: UGC will be dissolved. AICTE will be dissolved. NCTE will be dissolved. PCI will be dissolved.* So yes, the old chairmen era ends. No UGC Chairman. No AICTE Chairman. No NCTE Chairman. No PCI Chairman. Two clear exceptions: Medical education stays outside, under NMC. Law education stays outside, under BCI. Everything else comes under one umbrella. Now the new structure. There will be one national Chairperson at the top level under VBSAB. And there will be four councils, each with its own head. 1. NHERC (National Higher Education Regulatory Council) Approvals, permissions, compliance, entry and closure. 2. NAC (National Accreditation Council) Accreditation, institutional quality grading, credibility. 3. HEGC (Higher Education Grants Council) Funding ...