thermodynamics, chemistry,,physics

ഇവ Plus One THERMODYNAMICS – VERY SIMPLE PROBLEMS ആണ്
👉 Chemistry + Physics, step-by-step solutions സഹിതം 😊

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🔵 CHEMISTRY – Simple Thermodynamics Problems

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Q1. A system absorbs 100 J of heat and does 20 J of work.

Find ΔU.

Formula (Chemistry):

\Delta U = q + w

Given:
q = +100 J
w = –20 J (work done by system)

Solution:

\Delta U = 100 + (-20) = \boxed{80\ \text{J}}

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Q2. A system releases 50 J of heat and 30 J of work is done on it.

Find ΔU.

q = –50 J
w = +30 J

\Delta U = -50 + 30 = \boxed{-20\ \text{J}}

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Q3. At constant pressure, heat absorbed is 200 J.

Find ΔH.

Formula:

\Delta H = q_p

\Delta H = \boxed{200\ \text{J}}

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Q4. Is the reaction exothermic or endothermic if ΔH = –75 kJ?

👉 Exothermic reaction (heat released)

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🟢 PHYSICS – Simple Thermodynamics Problems

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Q5. A gas absorbs 500 J of heat and does 200 J of work.

Find ΔU.

Formula (Physics):

\Delta U = Q - W

Q = +500 J
W = +200 J

\Delta U = 500 - 200 = \boxed{300\ \text{J}}

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Q6. If Q = 0 and work done by gas = 100 J, find ΔU.

\Delta U = 0 - 100 = \boxed{-100\ \text{J}}

👉 This is an adiabatic process

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Q7. Heat supplied = 400 J, increase in internal energy = 150 J.

Find work done.

\Delta U = Q - W

150 = 400 - W

W = \boxed{250\ \text{J}}

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🟡 CHEMISTRY vs PHYSICS – Comparison Problems

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Q8. Same data:

Heat absorbed = 100 J
Work done by system = 40 J

Chemistry:

\Delta U = q + w = 100 - 40 = \boxed{60\ \text{J}}

Physics:

\Delta U = Q - W = 100 - 40 = \boxed{60\ \text{J}}

👉 Answer same, sign method different

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🧠 Exam Tips (VERY IMPORTANT)

✔ Write correct formula
✔ Use correct sign
✔ Mention unit (J or kJ)
✔ Don’t mix chemistry & physics sign conventions

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നിനക്ക് വേണമെങ്കിൽ:

• 📄 Worksheet with answers
• 🧮 More numericals (easy → exam level)
• 📖 Malayalam explanation
• 🎯 10-mark numericals practice set

ഏത് വേണമെന്ന് പറഞ്ഞാൽ മതി 😊